2x^2+(4x-6x^2)+9-(6x+3)=-4x-2x+6

Solution for 2x^2+(4x-6x^2)+9-(6x+3)=-4x-2x+6 equation:

2x^2+(4x-6x^2)+9-(6x+3)=-4x-2x+6

We move all terms to the left:

2x^2+(4x-6x^2)+9-(6x+3)-(-4x-2x+6)=0

We add all the numbers together, and all the variables

2x^2+(4x-6x^2)-(6x+3)-(-6x+6)+9=0

We get rid of parentheses

2x^2-6x^2+4x-6x+6x-3-6+9=0

We add all the numbers together, and all the variables

-4x^2+4x=0

a = -4; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·(-4)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*-4}=\frac{-8}{-8}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*-4}=\frac{0}{-8}
=0
$